Question

2. Add :

i. 3a²b² - 4ab + 5, 8a²b² + 12ab – 9 and

15 – 6ab – 5a²b²​

Answer 1

$\huge \star \; \bf \underbrace {ANSWER} \: \star$

‣ Given :

$\sf {Add \: :}$

$\sf {3a²b² - 4ab + 5, 8a²b² + 12ab - 9 \: and \: 15 - 6ab - 5a²b²}$

‣ To Find :

$\textsf {The resultant value}$

‣ Solution :

$\sf {(3a²b² - 4ab + 5) + (8a²b² + 12ab - 9) + (15 - 6ab - 5a²b²)}$

➡ $\textsf {Open brackets}$

$\sf {3a²b² - 4ab + 5 + 8a²b² + 12ab - 9 + 15 - 6ab - 5a²b²}$

➡ $\textsf {Collect like terms}$

$\sf {3a²b² + 8a²b² - 5a²b² - 4ab + 12ab - 6ab + 5 - 9 + 15}$

➡ $\textsf {Add like terms}$

$\sf {= \; 6a²b² + 2ab + 11}$

$\implies \sf {\underline {Hence, \: the \: answer \: is \: \; 6a²b² + 2ab + 11.}}$

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