Question

2. Add together 3ab+bc-ca, - ab+ca, ab-2bc+5ca. From
the sum take 5ca+bc-ab.​

Answer 1

Answer:

see the attachment

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Answer 2

4ab-2bc+0

Step-by-step explanation:

(3ab+bc-ca)+(-ab+ca)+(ab-2bc+5ca) = 3ab-bc+5ca

(3ab-bc+5ca) - (-ab+bc+5ca) =

4ab-2bc+0=

4ab-2bc