2 adjacent angles of a parellogrm are (3x-4)°&(3x+16).find the value of x&measure of each of its angle
Answers
Answered by
1
Hi ,
It is given that ,
( 3x - 4 )° and ( 3x + 16 )° are two
adjacent angles of a parallelogram.
We know that sum of two adjacent
angles in a parallelogram = 180°
3x - 4 + 3x + 16 = 180
6x + 12 = 180
6x = 180 - 12
6x = 168
x = 168/6
x = 28
Therefore ,
3x - 4 = 3 × 28 - 4 = 84 - 4 = 80°
3x +16 = 3 × 28 + 16 = 84 + 16 = 100°
Four angles of the parallelogram are
80° , 100° , 80° and 100°
I hope this helps you.
: )
It is given that ,
( 3x - 4 )° and ( 3x + 16 )° are two
adjacent angles of a parallelogram.
We know that sum of two adjacent
angles in a parallelogram = 180°
3x - 4 + 3x + 16 = 180
6x + 12 = 180
6x = 180 - 12
6x = 168
x = 168/6
x = 28
Therefore ,
3x - 4 = 3 × 28 - 4 = 84 - 4 = 80°
3x +16 = 3 × 28 + 16 = 84 + 16 = 100°
Four angles of the parallelogram are
80° , 100° , 80° and 100°
I hope this helps you.
: )
Similar questions