Question

2. after it rained heavily she started to go to market.

3. he went to bed after he completed his work.

4. before my father came i finished my dinner.

5. I met my family doctor when I fell seriously ill.

6. I locked the door when I went out to meet mt friend at a resturant..

hope it helps... plz mark me as brainliest...

Answer 1

Answer:

1. Fertilizers are chemical substances supplied to the crops to increase their productivity. These are used by the farmers daily to increase the crop yield. The fertilizers contain the essential nutrients required by the plants, including nitrogen, potassium, and phosphorus.
2. after it rained heavily she started to go to market.
4. 3. he went to bed after he completed his work.
6. 4. before my father came i finished my dinner.
8. 5. I met my family doctor when I fell seriously ill.
10. 6. I locked the door when I went out to meet mt friend at a resturant..

Answer 2

Answer:

Given :-

The sum of two angles of a triangle is 116° degree and their difference is 24 degree.

To Find :-

What is the measure of each angles of the triangle.

Solution :-

Let,

$\mapsto \bf First\: Angle =\: \angle{A}$

$\mapsto \bf Second\: Angle =\: \angle{B}$

According to the question,

$\bigstar$ The sum of two angles of a triangle is 116°.

$\footnotesize\implies \bf First\: Angle + Second\: Angle =\: 116^{\circ}$

$\implies \sf \angle{A} + \angle{B} =\: 116^{\circ}$

$\implies \sf\bold{\purple{\angle{A} + \angle{B} =\: 116^{\circ}\: ------\: (Equation\: No\: 1)}}$

Again,

$\bigstar$ The difference between two angles is 24°.

$\footnotesize \implies \bf First\: Angle - Second\: Angle =\: 24^{\circ}$

$\implies \sf \angle{A} - \angle{B} =\: 24^{\circ}$

$\implies \sf\bold{\purple{\angle{A} - \angle{B} =\: 24^{\circ}\: ------\: (Equation\: No\: 2)}}$

Now, as we know that :

$\footnotesize\bigstar\: \: \sf\boxed{\bold{\pink{Sum\: of\: all\: angles\: of\: triangle =\: 180^{\circ}}}}\: \: \bigstar$

According to the question by using the formula we get,

$\implies \sf \angle{A} + \angle{B} + \angle{C} =\: 180^{\circ}$

$\implies \sf 116^{\circ} + \angle{C} =\: 180^{\circ}\: \: \bigg\lgroup \small\sf\bold{From\: equation\: no\: 1}\bigg\rgroup$

$\implies \sf \angle{C} =\: 180^{\circ} - 116^{\circ}$

$\implies \sf\bold{\red{\angle{C} =\: 64^{\circ}}}$

Now, by putting the value of equation no 2 in the equation no 1 we get,

$\implies \sf \angle{A} + \angle{B} =\: 116^{\circ}$

$\implies \sf 24^{\circ} + 2\angle{B} =\: 116^{\circ}$

$\implies \sf 2\angle{B} =\: 116^{\circ} - 24^{\circ}$

$\implies \sf 2\angle{B} =\: 92^{\circ}$

$\implies \sf \angle{B} =\: \dfrac{\cancel{92^{\circ}}}{\cancel{2}}$

$\implies \sf \angle{B} =\: \dfrac{46^{\circ}}{1}$

$\implies \sf\bold{\red{\angle{B} =\: 46^{\circ}}}$

Again, by putting the value of ∠B in the equation no 1 we get,

$\implies \sf \angle{A} + \angle{B} =\: 116^{\circ}$

$\implies \sf \angle{A} + 46^{\circ} =\: 116^{\circ}$

$\implies \sf \angle{A} =\: 116^{\circ} - 46^{\circ}$

$\implies \sf\bold{\red{\angle{A} =\: 70^{\circ}}}$

${\footnotesize{\bold{\underline{\therefore\: The\: measure\: of\: each\: angles\: of\: a\: triangle\: is\: 70^{\circ}\: , 46^{\circ}\: and\: 64^{\circ}\: respectively\: .}}}}$

Answer 3

Answer:

Given :-

The sum of two angles of a triangle is 116° degree and their difference is 24 degree.

To Find :-

What is the measure of each angles of the triangle.

Solution :-

Let,

$\mapsto \bf First\: Angle =\: \angle{A}$

$\mapsto \bf Second\: Angle =\: \angle{B}$

According to the question,

$\bigstar$ The sum of two angles of a triangle is 116°.

$\footnotesize\implies \bf First\: Angle + Second\: Angle =\: 116^{\circ}$

$\implies \sf \angle{A} + \angle{B} =\: 116^{\circ}$

$\implies \sf\bold{\purple{\angle{A} + \angle{B} =\: 116^{\circ}\: ------\: (Equation\: No\: 1)}}$

Again,

$\bigstar$ The difference between two angles is 24°.

$\footnotesize \implies \bf First\: Angle - Second\: Angle =\: 24^{\circ}$

$\implies \sf \angle{A} - \angle{B} =\: 24^{\circ}$

$\implies \sf\bold{\purple{\angle{A} - \angle{B} =\: 24^{\circ}\: ------\: (Equation\: No\: 2)}}$

Now, as we know that :

$\footnotesize\bigstar\: \: \sf\boxed{\bold{\pink{Sum\: of\: all\: angles\: of\: triangle =\: 180^{\circ}}}}\: \: \bigstar$

According to the question by using the formula we get,

$\implies \sf \angle{A} + \angle{B} + \angle{C} =\: 180^{\circ}$

$\implies \sf 116^{\circ} + \angle{C} =\: 180^{\circ}\: \: \bigg\lgroup \small\sf\bold{From\: equation\: no\: 1}\bigg\rgroup$

$\implies \sf \angle{C} =\: 180^{\circ} - 116^{\circ}$

$\implies \sf\bold{\red{\angle{C} =\: 64^{\circ}}}$

Now, by putting the value of equation no 2 in the equation no 1 we get,

$\implies \sf \angle{A} + \angle{B} =\: 116^{\circ}$

$\implies \sf 24^{\circ} + 2\angle{B} =\: 116^{\circ}$

$\implies \sf 2\angle{B} =\: 116^{\circ} - 24^{\circ}$

$\implies \sf 2\angle{B} =\: 92^{\circ}$

$\implies \sf \angle{B} =\: \dfrac{\cancel{92^{\circ}}}{\cancel{2}}$

$\implies \sf \angle{B} =\: \dfrac{46^{\circ}}{1}$

$\implies \sf\bold{\red{\angle{B} =\: 46^{\circ}}}$

Again, by putting the value of ∠B in the equation no 1 we get,

$\implies \sf \angle{A} + \angle{B} =\: 116^{\circ}$

$\implies \sf \angle{A} + 46^{\circ} =\: 116^{\circ}$

$\implies \sf \angle{A} =\: 116^{\circ} - 46^{\circ}$

$\implies \sf\bold{\red{\angle{A} =\: 70^{\circ}}}$

${\footnotesize{\bold{\underline{\therefore\: The\: measure\: of\: each\: angles\: of\: a\: triangle\: is\: 70^{\circ}\: , 46^{\circ}\: and\: 64^{\circ}\: respectively\: .}}}}$