Question

(2+alpha² )(2+beta²)

Answer 1

Answer:

α+β=a,αβ=b

let equation whose roots are 2α+1,2β+1

be x

2

+Ax+B=0

then −A=(2α+1)+(2β+1)=0

−A=2(a)+2=2(a+1)

B=(2α+1)(2β+1)

=4αβ+2α+2β+1

=4b+2a+1

∴ required equation is

x

2

−2(a+1)x+4b+2a+1=0

Step-by-step explanation:

Hope it helps you dear..✦

Answer 2

Answer:

Thank you so much for free points dear..