2
Also show that (A U B'=AN B'.
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Step-by-step explanation:
Answer:
Both statements are true.
Step-by-step explanation:
1. A U (A ∩ B) = A ( to show)
Simplyfying LHS
A U (A ∩ B) = (A U A) ∩ (A U B) (distributive law)
= A ∩ (A U B)
Also, A intersection with A U B will always be A as A is the smaller set of the two.
So, A U (A ∩ B) = A
2. A ∩ (A U B) = A
Simplyfying LHS
A ∩ (A U B) = (A ∩ A) U (A ∩ B) (distributive law)
= A U (A ∩ B)
Also, A union with A ∩ B will always be A as A is the bigger set of the two.
So, A ∩ (A U B) = A
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