Question

2 & the filament of an
electrie lamp drains
a current of 0.5A which tights for
5 hours Caluulate the amount of charge
through the circuit​

Answer 1

✬ Charge = 9000 C ✬

Correct Question: The filament of an electric lamp drains a current of 0.5A which lights for 5 hours. Calculate the amount of charge through the circuit.

Explanation:

Given:

• Filament of an electric lamp drains current of 0.5 A.
• Lamp lights for 5 hours.

To Find:

• Amount of charge through circuit ?

Formula to be used:

• I = Q/t

Solution: Changing time into seconds.

➟ 1 hour = 3600 seconds

➟ 5 hours = 3600 × 5 = 18000 seconds

Here we have

• I = 0.5 A
• t = 18000 s
• Q = ?

Substituting the values on formula

$\implies{\rm }$ I = Q/T

$\implies{\rm }$ 0.5 = Q/18000

$\implies{\rm }$ 5/10 = Q/18000

$\implies{\rm }$ 5 × 18000/10 = Q

$\implies{\rm }$ 90000/10 = Q

$\implies{\rm }$ 9000 = Q

Hence, 9000 coulomb charge will flow through the circuit.

• S.I unit of current is ampere.
• S.I unit of charge is coulomb.

Answer 2

Answer:

✳️ Question ✳️

• The filament of an electric lamp drains a current of 0.5 A which tights for 5 hours. Calculate the amount of charge through the circuit.

✳️ Given ✳️

• The filament of an electric lamp drains a current of 0.5 A which tights for 5 hours.

✳️ To Find ✳️

• What is the amount of charge through the circuit.

✳️ Formula Used ✳️

$\green\bigstar$ I = $\dfrac{Q}{T}$

where,

• Q = Quantity of charge
• T = Time taken

✳️ Solution ✳️

First, we have to convert time into second :-

✒️ We know that, 1 hours = 3600 seconds

Then, 5 hours = 5 × 3600 = 18000 seconds

Given :-

• I = 0.5 A
• T = 18000 seconds

➕ According to the question by using the formula we get,

$\implies$ 0.5 = $\dfrac{Q}{18000}$

$\implies$ $\dfrac{5}{10}$ = $\dfrac{Q}{18000}$

✍️ By doing cross multiplication we get,

$\implies$ 10Q = 5 × 18000

$\implies$ Q = $\dfrac{5 × 18000}{10}$

$\dashrightarrow$ Q = 9000

$\therefore$ The amount of charge through the circuit is 9000 C.

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