Question

2. An advertisement board is 9 m long and 6 m broad. There are 1.5 m long lights along all
sides of it. Find the number of lights required to decorate the board,
(Hint: Number of lights - Perimeter of the rectangle + length of 1 light
​

Answer 1

Answer:

number of lights required to decorate the

board 20

Step-by-step explanation:

An advertisement board

L 9m long

B=6 m broad

perimeter of board= 2(L+B)

2(9+6)

2(15)

= 30 m

length of one light = 1.5 m= 15/10 m

number of lights required to decorate the

board perimeter of rectangle length of1

light

30/(15/10)

30x10/15

2x10

20

number of lights required to decorate the

board 20

Step-by-step explanation:

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