2. An airplane attains a velocity of 200 ms-1 in 30 s at the airstrip. Find its acceleration.
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Answered by
1
Answer:
u=0m/s , v= 200m/s time taken to attain the velocity=30s
therefore, a=v-u/t=(200/30)m/s^2= 6.66m/s^2
Answered by
0
Explanation:
here,
initial velocity (u)= 0 m/s
final velocity (v) = 200m/s
time = 30 s
so, acceleration= v- u divided by time
= 200- 0 divided by 30
= 6.66m/s2
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