Question

2) An altitude of a triangle is 5, the lenth
of its coresponding base. If the altitude is
increased by 4 cm and base decreased by
2 cm. The area remains the same find.
the altitude and base​

Answer 1

Answer:

1st case

altitude = 5, base = 4.5

2nd case

altitude = 9, base = 2.5

Step-by-step explanation:

1st case

altitude = 5

base = x

2nd case

altitude = 5 + 4 = 9

base = x - 2

area will be same

$\frac{1}{2} \times 5 \times x = \frac{1}{2} \times 9 \times (x - 2) \\ 5x = 9x - 18 \\ 5x - 9x = - 18 \\ - 4x = - 18 \\ 4x = 18 \\ x = \frac{18}{4} = 4.5$

1st case

altitude = 5, base = 4.5

2nd case

altitude = 9, base = 2.5