2.An athlete completes one round of a circular track of diameter 500m in 100s. What will be the displacement of an athlete at the end of 5mins?
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diametre of circular track, AB=200m.
Time taken to complete one round =40s
Total time =2min20s=(2×60+20)s=140s
Number of rounds completed =14040=3.5
Distance covered =2πr×3.5
=2×(22/7)×(200/2)×3.5m=2200m
If the athlete starts from A, on completion of 3.5 rounds, he will be at B.
Thus, displacement =AB−→−=200m (in magnitude).
Explanation:
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