Question

2. An electric bulb having resistance 200ohm draws a current of 2A. Find the power of the bulb whose potential difference at its ends and the energy(in kWh) consumed burning it for 4 hours a day?
with the formula please​

Answer 1

$power = {i}^{2} r \\ where \: i = current \\ r = resistance \\ power = {2}^{2} \times 200 \\ = 4 \times 200 \\ = 800 \: watt \\ energy = power \: \times time \\ = 800 \times 4 \\ = 3200 \: wh \\ = \frac{3200}{1000} \: kwh \\ = 3.2 \: kwh \\ potential \: difference = i \times r \\ = 2 \times 200 \\ = 400 \: volt$

please mark me brainliest.