Math, asked by TheUndefeatable, 7 months ago

2.An electric bulb of 60 W burns for 5 hours a day . The cost of electricity involved in a month of 30 days at 3.00 per unit

1.270

2.27

3.2.70

4.2700 ​

Answers

Answered by anjali5087
9

Answer:

Given:-

Power= 60 Watt

Everyday Use = 10 Hours

Total Days= 30

Cost Of elctricity per unit= 3.50 Rs.

Find:-

Total amount to be paid in 30 days

Given:-

The days can be calculated in total hours used in 30 days

Hence, Days x Everyday Use = 30 x 10 = 300 Hours

Convert, 60 Watt into Kwatt = 60/1000

By Formula,

Unit= Kwatt x Time (in hours)

U= 60/1000 x 300

U= 18

Hence, total unit used is 18.

By Formula,

Cost= Unit x Rupees per unit

Cost= 18 x 3.50

Cost= 63 Rupees

Therefore, the amount to pay in 30 days is 63 Rupees.

Answered by Anonymous
15

Answer:

Total Hours=30×5=150

Unit=60/1000×150=9 unit

Cost=9×3=27₹

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