Question

(2)

An electric iron uses power of 1500 w. when set to higher temperature,
it uses 250 w power. Find out the electric current and respective
resistance for the two settings. The iron is connected to a potential difference
on 150v.​

Answer 1

Explanation:

your answer is in the attachment

please mark it as BRAINLIEST

Answer 2

Answer:

p=vi

1500w=150×current

current=10A

PUTTING IN

V=IR

150=10×R

R=15ohm

setting 2

when P=250w

P=VI

250=150×I

I  =5/3 = 1.6A

PUTTING IN

V = IR [OHMS LAW]

150=5/3×r

R= 150×3/5

R= 90ohm

Explanation: