Question

2. An electric lamp of 100, and a water filter of resistance 500 are connected in parallel to
a 220v source. What is the resistance of an electric iron connected to the same source that
takes as much current as all three appliances & what is the current through it?
Ans​

Answer 1

Step-by-step explanation:

2. An electric lamp of 100, and a water filter of resistance 500 are connected in parallel to

a 220v source. What is the resistance of an electric iron connected to the same source that

takes as much current as all three appliances & what is the current through it?

Answer 2

Answer:

R1 =100 ohm ,R2 =50 ohm,R3 =500 ohm

Total 1/R = 1/R1+1/R2+1/ R3

1/R = 1/100+1/50+1/500

1/R= 16/500

where ,

R=500/16 ohm

(2) v directly proportional to I or V=it

R=v/I

R is resistance(constant)

v is potential difference

I is current

so,

500/16=220/I

I=220×16/500=7.04 A