Question

2.) An electrician has to repair an electric
fault on a pole of height 4 m. She needs
to reach a point 1.3 m below the top of
the pole to undertake the repair work.
What should be the length of the ladder
that she should use which, when inclined
at an angle of 60° to the horizontal, would
enable her to reach the required position?
Also, how far from the foot of the pole
should she place the foot of the ladder?

(You may take V3 = 1.73)
​

Answer 1

Answer:

Step-by-step explanation:

tan 60= AC/BC

√3    =2.7/BC

√3 BC = 2.7

BC = 2.7/√3

BC= 2.7/1.73

BC=1.56 m

sin 60= AC/AB

√3/2 = 2.7/AB

2 x 2.7 = √3 AB

AB=5.4/√3

AB = 5.4/1.73

AB=3.29

THEREFORE THE LENGTH OF THE LADDER SHOULD BE 3.29

AND DISTANCE BETWEEN FOOT OF LADDER AND POLE IS 1.56