Question

2. An elevator descends into a mine shaft at the rate of 8 m/min. If the descent starts from 10 m above
the ground level, how long will it take to reach - 390 m, 3M​

Answer 1

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An elevator descends into a mine shaft at the rate of 8 m/min. If the descend starts from 12 m above the ground level, how long will it take to reach −468 m?

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Answer

Correct option is

A

60 mins

Total distance covered from A to C =12+468=480 m

Speed =8 m/min

Therefore, time =

Speed

Total distance covered

time=

8

480

=60 minutes.