Question

2
An ideal gas undergoes a
cyclic process KLMNK as
shown in given P-V diagram.
The amount of work done by
the gas is :
(a) +6P. V. (b) -2P, V.
(c) +2P, V (d) +4P, V.
Ppt
V.
V_
3V,​

Answer 1

Answer:

Work done by the gas in the above cyclic process is -2PoVo

Explanation:

As we know that work done by the gas is given as

$W = \int PdV$

here we know that this above integral will be equal to the area of the graph between pressure and volume

So we can say that here the area of the loop or the curve will be equal to the work done by the gas

Also here we know that the area of the curve during expansion of gas is smaller than the area of the curve during compression of the gas

So overall the work done by the gas must be negative work

so we have

$W = - (2P_o - P_o)(3V_o - V_o)$

$W = -2P_oV_o$

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Topic : work done by ideal gas

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