2. An inductor of 3 henrys is in series wih a resistance of 30 ohms and an e.mf. of 150 volts. Assuming that at t=0, the current is zero. Find the current at time t>0.
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Step-by-step explanation:
Let I be current at ant time t
EMF E=5 volts , resistance R=50 ohms and inductance L=1 henry
The basic equation of current for RL circuit
is dl + R I = E
dt L L
=> dl + 50I = 5
dt
This is a linear equation and the solution of it is I=ce
−50t + ⅒
At t=0 , I=0. So we get c = - ⅒
Therefore the equation for current will become I = - ⅒e - ⁵⁰t + ⅒
As t tends to infinite , the value of I tends to ⅒
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Step-by-step explanation:
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