2. An object having height of 6 cm is placed at 50 cm in
front of concave mirror having focal length of 20 cm. Find
the position, nature and size of an image.
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Explanation:
Height of object = +6 cm
Object distance = -50 cm
Focal length = +30 cm
Lens formula = 1/f = 1/v - 1/u
1/v = 1/f + 1/u
1/v = 1/30 - 1/50
= 5-3/150
= 2/150
Image distance = 150/2 = +75.5 cm
height of image = image distance
height of object object distance
h = 75.5 x 6
- 50
h = +9.06 cm
Hence image formed is virtual, erect, and magnified
Hope it helps!!H!
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