Question

2. An object is placed at 5 em from a concave mirror of focal length 10 cm. Find the position and nature of image formed. Draw a ray diagram to explain the formation of image Inot to scale). ​

Answer 1

Answer:

The position of the image is 10 cm to the backside of the mirror. The image formed will be virtual, erect, and magnified.

Explanation:

The object distance, u = -5 cm

The focal length, f = -10 cm

The image distance can be found using the mirror formula as:

1/f = 1/u + 1/v

1/v = 1/f - 1/u

∴ v = uf / (u - f)

  v = (-5 × -10) / (-5 - - 10)

  v = 50 / 5 = +10 cm

Since the sign of image distance is positive, we can say that it is formed on the backside of the mirror. So the image will be virtual. Virtual images will also be erect. The image formed will be a magnified one than the object as shown in the ray diagram.