Question

2
An object is placed at a distance of 10cm from a convex mirror of focal
length 15 cm. find the position and nature of image *
60 cm, real & inverted
O ,
0.6 cm , erect & virtual
O 6 cm, erect & Virtual
O 0.06 cm , real & inverted​

Answer 1

Explanation:

It is to be remembered that a convex mirror always forms the virtual, erect and diminished image.

Given: Object distance, u=−10cm Focal length, f=15cm

To find: Image distance, v

From mirror formula :

v

1

+

u

1

=

f

1

v

1

−

10

1

=

15

1

v

1

=

15

1

+

10

1

=

150

25

v=6cm

Hence image will be formed 6 cm beyond the mirror, i.e virtual magnification

m=

u

−v

=

−10

−6

=0.6

Hence it will be erect and diminished.

Answer 2

Answer:

use formula 1/f =1/v+1/u

Explanation:

since its a convex mirror f is -ve that is -15 cm and image distance is always negative is -10 cm

so -1/15 =1/v + -1/u use this apply value and find v and v value is negative its real inverted n if postive its virtual erect.