Question

2. an object travels 120 m with an initial velocity of 10 m/s for time 2 second ,find the acceleration and final velocity also.​

Answer 1

Answer:

a=50cm/sec^2

v=110cm/sec

Explanation:

s=ut+1/2at^2

120=10(2)+1/2a4

120=20+2a

a=50cm/sec^2

v=u +at

=10+50(2)

v=110cm/sec

Answer 2

$\rm \huge\blue{ \bold{Answer}}$

✒ Given:

✏ distance travelled by an object = 120m

✏ initial velocity = 10 m/s

✏ time interval = 2 s

✒ To Find:

1. acceleration
2. final velocity

✒ Formula:

✏ Kinematics equations are provided below...

$\: \: \: \: \: \: \: \: \: \underline{ \boxed{ \bold{ \rm{ \pink{d = ut + \frac{1}{2} a{t}^{2} }}}}} \: \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \underline{ \boxed{ \bold{ \rm{ \red{v = u + at}}}}} \:$

✒ Calculation:

1) Acceleration

$\implies \rm \: 120 =( 10 \times 2) + \frac{1}{2} a({2})^{2} \\ \\ \implies \rm \: 120 = 20 + 2a \\ \\ \implies \rm \: 100 = 2a \\ \\ \therefore \: \underline{ \boxed{ \bold{ \rm{ \purple{a = 50 \: \frac{m}{ {s}^{2} } }}}}}$

2) Final velocity

$\implies \rm \: v = 10 + (50 \times 2) \\ \\ \implies \rm \: v = 10 + 100 \\ \\ \therefore \: \underline{ \boxed{ \bold{ \rm{ \green{v = 110 \: \frac{m}{s} }}}}}$