Question

2. An organic compound contains 50% oxygen and
12.5% hydrogen by mass, then mole fraction of
hydrogen in the compound would be
​

Answer 1

Hi,

Answer:

The mole fraction of hydrogen in the compound is 0.798.

Explanation:

Given data:

% of oxygen in the organic compound = 50% by mass

% of hydrogen in the organic compound = 12.5% by mass

To find: Mole fraction of hydrogen in the compound

For simplicity purpose, we will consider the quantity of the organic compound to be 100 g.

Let the no. of moles of oxygen be “n1” and no. of moles of hydrogen be “n2”.

So,  

No. of Moles of oxygen, n1 = [50% * 100] / 16 = 3.125 mol

No. of Moles of hydrogen, n2 = [12.5% * 100] / 1.008 = 12.40 mol

∴ Mole fraction of hydrogen in the compound ,

χ of hydrogen  

= n2 / [n1+n2]  

= 12.40 / [12.40+1.008]

= 12.40 / 15.525

= 0.798

Hope this helps!!!!

Answer 2

Answer:

The mole fraction of hydrogen in the compound is 0.798.

Explanation:

Given data:

% of oxygen in the organic compound = 50% by mass

% of hydrogen in the organic compound = 12.5% by mass

To find: Mole fraction of hydrogen in the compound

For simplicity purpose, we will consider the quantity of the organic compound to be 100 g.

Let the no. of moles of oxygen be “n1” and no. of moles of hydrogen be “n2”.

So,  

No. of Moles of oxygen, n1 = [50% * 100] / 16 = 3.125 mol

No. of Moles of hydrogen, n2 = [12.5% * 100] / 1.008 = 12.40 mol

∴ Mole fraction of hydrogen in the compound ,

χ of hydrogen  

= n2 / [n1+n2]  

= 12.40 / [12.40+1.008]

= 12.40 / 15.525

= 0.798

Hope this helps!!!!