Math, asked by sunny9734, 11 months ago

2)An urn contains 6 red balls and 3 blue balls. One ball is selected at random and is replaced by a ball of the other color. A second ball is then chosen. What is the conditional probability that the first ball selected is red, given that the second ball was red?

Answers

Answered by udita10611
0

Answer:1/2

Step-by-step explanation:

Answered by amitnrw
0

10/17 is conditional probability that the first ball selected is red, given that the second ball was red

Step-by-step explanation:

An urn contains 6 red balls and 3 blue balls

Let say first ball Selected is Red

the Probability = 6/9 = 2/3

Then Balls in Urn  = 5 Red Balls + 4 Blue Balls

Probability of Red Balls = 5/9

Probability of Red Ball in case 1 = (2/3)(5/9)  = 10/27

Let say first ball Selected is Blue

the Probability = 3/9 = 1/3

Then Balls in Urn  = 7 Red Balls + 2 Blue Balls

Probability of Red Balls = 7/9

Probability of Red Ball in case 1 = (1/3)(7/9)  = 7/27

Probability of Red Ball = 10/27  + 7/27  = 17/27

Probability of red ball when first ball selected was red = 10/27

conditional probability that the first ball selected is red, given that the second ball was red  = (10/27)/(17/27)

= 10/17

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