Math, asked by samirkansara826, 7 months ago

-√2 and √2 are two zeros of P ( x ) = 2x^4 +7x^3-8x^2-14x+8
, find remaining zeros of P(x)

Answers

Answered by dunukrish

2

Step-by-step explanation:

The remaining two zeroes are -4 and 1/2

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