Question

2 and -3 are the zeros of qadratic ploynial x2 +(a+1)

Answer 1

Step-by-step explanation:

Zeroes: -3 and 2

Sum of zeroes = 2 - 3

==> -1

Product of zeroes = -3 × 2

==> -6

p(x) = x² - ( sum of zeroes )x + ( product of zeroes )

==> p(x) = x² - (-1)x + (-6)

==> p(x) = x² + x - 6