Question

2 and -3 are zeroes of quadratic poly x×x+(a+1)×x+b then find value of a and b

Answer 1

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♦ Factor Theorem :
 → p( x ) = x² + ( a + 1 )x + b

◘ Since, '2' is a zero, applying factor theorem :
  → p( 2 ) = 0

Solve for x = 2, to get : 6 + 2a + b = 0

→ Similarly, for x = -3,   6 - 3a + b = 0

Solving for 'a',   a = 0,  b = -6
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=> a = 0 , b = -6 is your required solution
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Must Read : ♦ Factor Theorem ♦