Question

2 and 3 are zeros of the polynomial p(x)=(x-2) (x-3). verify​

Answer 1

Step-by-step explanation:

p(x)= x²-2x-3x+6

= x²-5x+6

p(2)= 2²-5(2)+6

= 4-10+6

= 10-10

= 0

p(3)= 3²-5(3)+6

= 9-15+6

= 15-15

= 0

Answer 2

Answer:

For verification,we have

Step-by-step explanation:

given,

x-2=0

for x=2,we have

2-2=0

hence proved