Question

2 and 4 by 5 + 13 by 15 + 25 by 30​

Answer 1

Answer:

Find the sum:

(i) 5/4 + (-11/4)

(ii) 5/3 + 3/5

(iii) -9/10 + 22/15

(iv) -3/(-11) + 5/9

(v) -8/19 + (-2)/57

(vi) -2/3 + 0

(vii) -2 1/3 + 4 3/5

Solution:

To solve this question, we will take the L.C.M of denominator or convert the given fractions into like fractions.

(i) 5/4 + (-11/4)

= 5/4 -11/4

= (5 - 11)/4

= - 6/4

= - 3/2

(ii) 5/3 + 3/5

Taking L.C.M of 3 and 5 , we get 15

5/3 + 3/5

= (5 × 5)/(3 × 5) + (3 × 3)/(5 × 3)

= 25/15 + 9/15

= (25 + 9)/15

= 34/15

(iii) -9/10 + 22/15

Taking L.C.M of 10 and 15 , we get 30

-9/10 + 22/15

= (- 9 × 3)/30 + (22 × 2)/30

= -27/30 + 44/30

= 17/30

(iv) -3/(-11)+ 5/9

Taking L.C.M of 11 and 9 , we get 99

-3/(-11)+ 5/9

= (-3 × 9)/(-99) + (5 × 11)/99

= 27/99 + 55/99

= 82/99

(v) - 8/19 + ( -2)/57

Taking L.C.M of 19 and 57, we get 57

-8/19 + ( -2)/57

= (-8 × 3)/(19 × 3) + (-2 × 1)/(57 × 1)

= -24/57 + (-2/ 57)

= (-24 - 2)/57

= -26/57

(vi) -2/3 + 0

Taking L.C.M of 3 and 1, we get 3

-2/3 + 0

= (-2 × 1)/3 + (0 × 3)/3

= -2/3 + 0/3

= (-2 + 0)/3

= -2/3

(vii) -

2

1

3

+

4

3

5

= -7/3 + 23/5

Taking L.C.M of 3 and 5, we get 15

= (-7 × 5)/15 + (23 × 3)/15

= -35/15 + 69/15

= (-35 + 69)/15

= 34/15

Answer 2

Answer:

$2 \frac{4}{5 } + \frac{13}{15} + \frac{25}{30}$

$\frac{14}{5} + \frac{13}{15} + \frac{25}{30}$

$\frac{14 \times 6 + 13 \times 2 + 25}{30}$

$\frac{84 + 26 + 25}{30}$

$\frac{135}{30}$

$4\frac{15}{30}$