Question

2. α and β are zeroes of x2 +(kx +6)x +(4k-2), then find the value of k if- a) roots are reciprocal of each other b) if α+ β = α β

Answer 1

Answer:

use only this formula same

Step-by-step explanation:

At first you have to understand what's the Basic formula for Quadratic Equation? I guess you have confusion in basics that's why you posted this question. So, am just giving you a glimpse about the chapter so that you can understand the whole concept better.

Ax2+Bx+C=0 where a,b,c are contsants & say roots of the equation are α and β

Using roots of the equation you can form equation:- x2−(α+β)x+αβ=0

Where, α+β=−B/A & C = C/A

Now coming to your question:-

x2–(k+6)x+2(2k−1)=0

Here, α+β = (K+6) & αβ=2(2k−1) also given, α+β = ½( αβ )

i.e, (K+6) = ½ × 2 (2K-1)

=> K = 7