Question

2. Angle BAC=90°, AD perpendicular BC and angle BAD = 50° then angle ACD is?​

Answer 1

Answer:

50 degree

Step-by-step explanation:

From the question it is given that, ∠BAC = 90o AD ⊥ BC and ∠BAD = 50o So, ∠DAC = ∠BAC – ∠BAD = 90o – 50o = 40o The, consider the ΔADC From the rule of exterior angle property = ∠ADB = ∠DAC + ∠ACD 90o = 40o + ∠ACD ∠ACD = 90 – 40 ∠ACD = 50 degree