Question

2. Anirban travelled 1/2 km on foot and 4hole 2/5 km by bus to reach his school, How far did he travel to
reach his school?​

Answer 1

Step-by-step explanation:

Total distance covered by Anirban -

$= \: \: \frac{1}{2} + 4\frac{2}{5} = \frac{1}{2} + \frac{22}{5} \\ \\ = \frac{1 \times 5}{2 \times 5} + \frac{22 \times 2}{5 \times 2} \\ \\ = \frac{5}{10} + \frac{44}{10} \\ \\ = \frac{49}{10} = 4\frac{9}{10} \: km$

Therefore, Anirban travel 4 whole 9/10 km

Answer 2

Answer:

Answer = 4.9km

Step-by-step explanation:

Distance covered by Anirban on foot = 1/2 km

Distance covered by bus = 22/5 km

Distance travelled to reach his school = 1/2+22/5

Then take L.C.M

L.C.M of 2 and 5 = 10

1/2×5/5+22/5×2/2

5/10+44/10

49/10

4.9km