Math, asked by rekhasharma1765, 3 months ago

2) Answer the questions based on the table.
Name of the ride Price
Time
Toy train
20
10 minutes
Dancing car
30
10 minutes
Boating
25
10 minutes
1. You have Rs. 200. What is the maximum number of tickets you can buy for a
dancing car?
2. If you sit once in each ride what is the total cost of the ride?
3. How many times can you go for boating in Rs 75?​

Answers

Answered by meghtrivedi1204
16

Answer:

for 1 question answer we have total Rupees 200

next No of tickets we want to buy for dancing car in 200 rupees is i ride is for 30 rupees so 200/30 equals to is maximum 6 tickets so can buy

for 2 question answer is if we sit in each ride the total cost equals to ?

so for 1 ride we need 20 rupees for 2 ride we need 30 rupees and for third we need 25 rupees so when we add these all we get sum of 75 rupees

for 3 question answer is for one time to enjoy boat ride it costs 25 rupees and we have 75 rupees so when we divide 75 by 25 we can ride it for 3 times I hope it helps you all

Answered by RvChaudharY50
10

Given :-

Name of the ride Price Time

Toy train 20 10 minutes

Dancing car. 30 10 minutes

Boating 25 10 minutes

  • You have Rs. 200. What is the maximum number of tickets you can buy for a dancing car ?
  • If you sit once in each ride what is the total cost of the ride ?
  • How many times can you go for boating in Rs.75 ?

Solution :-

→ Price of dancing car = Rs.30

so,

→ In Rs.200 , total number of tickets can buy = (200/30) = 20/3 = 6.66 ≈ 6 tickets. (Ans.1)

now,

→ Total cost of all rides = Toy train price + dancing car price + boating price = 20 + 30 + 25 = Rs.75 (Ans.2)

also,

→ cost of Boating = Rs.25

then,

→ Total times we can go for boating in Rs.75 = 75 / 25 = 3 times. (Ans.3)

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