Biology, asked by muhammadkamranparvan, 3 months ago

2
are
dominant to ebony color, while long wings
In drosophilla gray body coloris
dominant to vestigial wing .193 surning
individuals ove hemory jous ,
work the following crosses through the
F2 generation, and determine
genotypic and phenotypic ratio for
each generation

Answers

Answered by triphatiarti98
0

Answer:

I don't have a idea

Explanation:

but i tell you

Answered by jessica12345679
1

Answer:

According to the question, parents are gray, short-winged fly and a black, long-winged fly. Since gray body color is dominant over black and long wings are dominant over short, the parents are homozygous for these recessive traits. The genotype of a parent with gray, short-wing is Ggll and that of black, the long-winged fly is ggLl. The ratio of black and gray progeny is 1:1 (25 percent gray, long wing and 25 percent gray, short wing: 25 percent black, short wing; and 25 percent black, long wing). Likewise, the ratio of progeny with short and long wings is also 1:1. A cross between heterozygous dominant and homozygous recessive gives 1 dominant: 1 recessive progeny. This means the parent fly with gray, short-wings is heterozygous for the body color and the parent fly with black, long-wings is heterozygous for wing length. Therefore, the genotype of the parent with gray, short-wing is Ggll and that of black, the long-winged fly is ggLl.

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