Question

2, Area of a parallelogram ABCD is 12.cm² and p is a point on side Bc what is the are of triangle apd
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Answer 1

Answer:

6cm²

Step-by-step explanation:

area of parallelogram= base × height

let AD be base and the height corresponding to it be h.

now, AD × H= 12

area of triangle =  base × height/2

=> AD × H/2 = 12/2= 6cm²

Answer 2

Answer:

6cm^2

triangle APD and parallelogram ABCD share common base AD. So, area of triangle APD is half the area of ABCD.

This is because area of ABCD=base multiplied by height and area of triangle APD= 1/2(base multiplied by height)=1/2(area of parallelogram ABCD)