Question

(2) Area of rectangle
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Answer 1

Answer:

2 * length * breadth

ok I hope you understand

Answer 2

Hello mate..

Answer:

The diagonals of the rectangle divide it into two equivalent right-angled triangles. Therefore, the area of the rectangle will be equal to the sum of the area of these two triangles.

The diagonals of the rectangle divide it into two equivalent right-angled triangles. Therefore, the area of the rectangle will be equal to the sum of the area of these two triangles.Suppose, ABCD is a rectangle.

The diagonals of the rectangle divide it into two equivalent right-angled triangles. Therefore, the area of the rectangle will be equal to the sum of the area of these two triangles.Suppose, ABCD is a rectangle. Area of Rectangle using Length and Breadth

The diagonals of the rectangle divide it into two equivalent right-angled triangles. Therefore, the area of the rectangle will be equal to the sum of the area of these two triangles.Suppose, ABCD is a rectangle. Area of Rectangle using Length and BreadthNow, let diagonal AC divide the rectangle into two right triangles, i.e. ∆ABC and ∆ADC.

The diagonals of the rectangle divide it into two equivalent right-angled triangles. Therefore, the area of the rectangle will be equal to the sum of the area of these two triangles.Suppose, ABCD is a rectangle. Area of Rectangle using Length and BreadthNow, let diagonal AC divide the rectangle into two right triangles, i.e. ∆ABC and ∆ADC.We know that, ∆ABC and ∆ADC are congruent triangles.

The diagonals of the rectangle divide it into two equivalent right-angled triangles. Therefore, the area of the rectangle will be equal to the sum of the area of these two triangles.Suppose, ABCD is a rectangle. Area of Rectangle using Length and BreadthNow, let diagonal AC divide the rectangle into two right triangles, i.e. ∆ABC and ∆ADC.We know that, ∆ABC and ∆ADC are congruent triangles.Area of ∆ABC = ½ x base x height = ½ x AB x BC = ½ x b x l

The diagonals of the rectangle divide it into two equivalent right-angled triangles. Therefore, the area of the rectangle will be equal to the sum of the area of these two triangles.Suppose, ABCD is a rectangle. Area of Rectangle using Length and BreadthNow, let diagonal AC divide the rectangle into two right triangles, i.e. ∆ABC and ∆ADC.We know that, ∆ABC and ∆ADC are congruent triangles.Area of ∆ABC = ½ x base x height = ½ x AB x BC = ½ x b x lArea of ∆ADC = ½ x base x height = ½ x CD x AD = ½ x b x l

The diagonals of the rectangle divide it into two equivalent right-angled triangles. Therefore, the area of the rectangle will be equal to the sum of the area of these two triangles.Suppose, ABCD is a rectangle. Area of Rectangle using Length and BreadthNow, let diagonal AC divide the rectangle into two right triangles, i.e. ∆ABC and ∆ADC.We know that, ∆ABC and ∆ADC are congruent triangles.Area of ∆ABC = ½ x base x height = ½ x AB x BC = ½ x b x lArea of ∆ADC = ½ x base x height = ½ x CD x AD = ½ x b x lArea of rectangle ABCD = Area of ∆ABC + Area of ∆ADC

The diagonals of the rectangle divide it into two equivalent right-angled triangles. Therefore, the area of the rectangle will be equal to the sum of the area of these two triangles.Suppose, ABCD is a rectangle. Area of Rectangle using Length and BreadthNow, let diagonal AC divide the rectangle into two right triangles, i.e. ∆ABC and ∆ADC.We know that, ∆ABC and ∆ADC are congruent triangles.Area of ∆ABC = ½ x base x height = ½ x AB x BC = ½ x b x lArea of ∆ADC = ½ x base x height = ½ x CD x AD = ½ x b x lArea of rectangle ABCD = Area of ∆ABC + Area of ∆ADCArea (ABCD) = 2(½ x b x l)

The diagonals of the rectangle divide it into two equivalent right-angled triangles. Therefore, the area of the rectangle will be equal to the sum of the area of these two triangles.Suppose, ABCD is a rectangle. Area of Rectangle using Length and BreadthNow, let diagonal AC divide the rectangle into two right triangles, i.e. ∆ABC and ∆ADC.We know that, ∆ABC and ∆ADC are congruent triangles.Area of ∆ABC = ½ x base x height = ½ x AB x BC = ½ x b x lArea of ∆ADC = ½ x base x height = ½ x CD x AD = ½ x b x lArea of rectangle ABCD = Area of ∆ABC + Area of ∆ADCArea (ABCD) = 2(½ x b x l)Area (ABCD) = l x b

The diagonals of the rectangle divide it into two equivalent right-angled triangles. Therefore, the area of the rectangle will be equal to the sum of the area of these two triangles.Suppose, ABCD is a rectangle. Area of Rectangle using Length and BreadthNow, let diagonal AC divide the rectangle into two right triangles, i.e. ∆ABC and ∆ADC.We know that, ∆ABC and ∆ADC are congruent triangles.Area of ∆ABC = ½ x base x height = ½ x AB x BC = ½ x b x lArea of ∆ADC = ½ x base x height = ½ x CD x AD = ½ x b x lArea of rectangle ABCD = Area of ∆ABC + Area of ∆ADCArea (ABCD) = 2(½ x b x l)Area (ABCD) = l x b Thus, the area of the rectangle = Length x Breadth