Question

2.Arjun had some chocolates with him. He gave one fourth of them to Arun and one-sixth of them to Varun. Arjun could do so without breaking any chocolate. Which of these could be the number of chocolates Arjun had in the beginning?

Answer 1

Answer:

Silly Question......

Answer 2

Answer:

Concept: solving the question by taking the question asked as a function i.e. x

GIVEN: Arjun gave one-fourth to Arun and one-sixth to Varun.

TO FIND: number of chocolates Arjun had in the beginning.

Step-by-step explanation:

let the chocolates Arjun had in the beginning be x .

he gave one-fourth to Arun i.e. $\frac{1}{4}x$  

and he gave one-sixth to Varun i.e. $\frac{1}{6}x$

and he have total number of chocolates is x .

so we can say that the total number of chocolates is  $\frac{1}{4}x+ \frac{1}{6}x$

or, $\frac{3x+2x}{12}$

or, $\frac{5x}{12}$

or, $x=\frac{12}{5}$⇒ $2.4$

∴ he  had 2.4 i.e. 3(approx) number of chocolates.  

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