Question

2. At a certain rate of simple interest, 21600 becomes 2200 in 9/2 years. What sum of moneywill become 5025 in 4 years and 9 months at the same rate of interest?

Answer 1

Answer:

$\huge\underline\mathfrak\pink{♡Solution♡}$

$\huge\underline\mathbb\blue{♡Given♡}$

• Principle P = Rs. 1600, period n = 9/2 years, Amount A = Rs2200

$\huge\underline\mathfrak\pink{♡Let's\:find ♡}$

Interest = Amount - Principle = 2200 - 1600 = 600

Interest = PnR/100 = 1600×(9/2)×(R/100) = 600 hence R = (25/3) %

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For second part, n = 19/4 year, Amount = Rs. 5025

P + PnR/100 = P [1+ ( nR/100 ) ] = P { 1 + [ (19/4)×(25/3)/100 ] } = 5025

$\huge\underline\mathfrak\green{HeNce♡}$

Solving the above equation for P, we get P = Rs. $\pink{3600}$