Question

2) At a certain rate of simple interest Rs 1600 becomes 2200 in 4 ½ years. What sum of money will becomes Rs 5025 in<br />4 years and 9 months at the same rate of Interest​

Answer 1

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$\underline{\large\mathcal\red{solution}}$

Let the rate is =r

now .....

$2200 = 1600(1 + \frac{r}{100} ) {}^{ \frac{9}{2} } \\ = > \frac{2200}{1600} = (1 + \frac{r}{100} ) {}^{ \frac{9}{2} } \\ = > (1 + \frac{r}{100} ) {}^{ \frac{9}{2} } = \frac{11}{8} \\ = > (1 + \frac{r}{100} ) = ( \frac{11}{8} ) {}^{ \frac{2}{9} }$

now ....

p'=5025(1+r/100)^4.9

p'=5025(11/8)^4.9/4.5

p'=7107.753 Rs

$\large\mathcal\red{hope\: this \: helps \:you......}$