Question

2
.
At a harbor, enemy ship is at a distance 180 √3 m
from the security cannon having a muzzle velocity of 60
m/s (a) To what angle must the cannon be elevated to
hit the ship ? (b) What is the time of flight? (c) How far
should the ship be moved away from its initial position
so that it becomes beyond the range of the cannon ?
(g = 10 m/s^2)​

Answer 1

Answer:

a)theta = 30° or 60°

b)time = 6 sec or 10.4 sec

c)shift in position=48.6m