Question

2. At what temperature will the molar kinetic energy of
0.3 mol of He be the same as that of 0.4 mol of argon at
400 K?.​

Answer 1

Answer:

KE = 3nRT/2

(KE)He /(KE)Ar = (moles of He)(temp of He)/(moles of Ar)(temprature of Ar)

1 = (0.3)T/(0.4)(400)

T = 400*4/3

=533K

HOPE IT HELPS✌✌✌✌

PLZ MARK AS BRAINLIEST