Question

2(ax-by)+(a+4b)= 0 ; 2(bx +ay) + (b -4a) = 0 solve by cross multiplication method *​

Answer 1

Answer:

2(ax-by) + (a+4b)=0 eqn1

2(bx+ay)+(b-4a)=0 eqn2

Multiplying eqn 1and2

we get,

= 4(ax-by) (bx+ay)+(a+4b)(b-4a)

=(ax-bx)(bx+ay)+(a+4b)+b

=by+bx+(a+5b)

=2xy+(a+5b)

Answer 2

Step-by-step explanation:

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