Chemistry, asked by shivrajsolanki1761, 5 months ago

2. Balance the following redox reactions in acidic medium. Cu (s) +NO 3(aq) ^ - +Cu (aq) ^ 2+ +NO (g) ) [By ion electron method]​

Answers

Answered by shinchan4448
4

Explanation:

ANSWER

The unbalanced redox equation is as follows:

Cu+NO

3

→Cu

2+

+NO

2

All atoms other than H and O are balanced.

The oxidation number of Cu changes from 0 to 2. The change in the oxidation number of Cu is 2.

The oxidation number of N changes from 5 to 4. The change in the oxidation number of N is 1.

The increase in the oxidation number is balanced with decrease in the oxidation number by multiplying NO

3

and NO

2

with 2..

Cu+2NO

3

→Cu

2+

+2NO

2

O atoms are balanced by adding 2 water molecule on RHS.

Cu+2NO

3

→Cu

2+

+2NO

2

+2H

2

O

To balance H atoms, add 4 H

+

on LHS.

Cu+2NO

3

+4H

+

→Cu

2+

+2NO

2

+2H

2

O

Since the reaction occurs in basic medium, add 4 hydroxide ions on both sides of the equation.

Cu+2NO

3

+4H

+

+4OH

→Cu

2+

+2NO

2

+2H

2

O+4OH

On LHS, 4 H

+

ions combine with 4 OH

ions to form 4 water molecules out of which 2 water molecules cancel out with 2 water molecules on RHS.

Cu+2NO

3

+2H

2

O→Cu

2+

+2NO

2

+4OH

This is the balanced chemical equation.

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