Question

2 balls have masses of 50 gm and 100 gm and they are moving along the same line in the same direction with velocities of 3m/s and 1.5 m/s respectively.They collide with each other and after the collision,the first ball moves with a velocity of 2.5 m/s,Calculate the velocity of the other ball after collision....or ha ata hai to do...vrna niklo!​

Answer 1

Answer:

Answer: 1.75m/s

Explanation:let u1 and u2 are velocity of balls before collision..Let after collision velocity of two balls are v1 and v2 .

From linear momentum conservation we get

m1u1+m2u2=m1v1+m2v2

m1 =50gm,u1=3m/s , v1=2.5m/s

Me=100gm, u2=1.5m/s, be=??

50×3+100×1.5=50×2.5+100×v2

150+150=125+100v2

300=125+100v2

175=100v2

V2 =175/100

V2 = 1.75

Hence velocity of 2nd particle after collision is 1.75m/s

Answer 2

Answer: 1.75m/s

Explanation:

• let u1 and u2 are velocity of balls before collision..Let after collision velocity of two balls are v1 and v2 .

From linear momentum conservation we get :-

• m1u1+m2u2=m1v1+m2v

• m1 =50gm,u1=3m/s , v1=2.5m/s

• Me=100gm, u2=1.5m/s, be=??

• 50×3+100×1.5=50×2.5+100×v2

• 150+150=125+100v2

• 300=125+100v2

• 175=100v2

• V2 =175/100

• [V2 = 1.75]

Hope it helps u

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