2 balls have masses of 50gm and 100gm respectively and they are moving along the same line in the same direction with velocities of 3m/sec and 1.5m/sec respectively. They collide with each other and after collision, the 1st ball moves with a velocity of 2.5m/sec. Calculate the velocity of the other ball after collision.
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Answer: 1.75m/s
Explanation:let u1 and u2 are velocity of balls before collision..Let after collision velocity of two balls are v1 and v2 .
From linear momentum conservation we get
m1u1+m2u2=m1v1+m2v2
m1 =50gm,u1=3m/s , v1=2.5m/s
Me=100gm, u2=1.5m/s, be=??
50×3+100×1.5=50×2.5+100×v2
150+150=125+100v2
300=125+100v2
175=100v2
V2 =175/100
V2 = 1.75
Hence velocity of 2nd particle after collision is 1.75m/s
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