Question

(_____)^ 2=(base)^ 2+(perpendicular)^2 ​

Answer 1

Answer:

(hypotenuse)² = (base)² + ( perpendicular)²

→ by Pythagoras theorem, in a right angled ∆ , the square of the hypotenuse is equal to the sun of the squares of remaining two sides.

or,

h² = p² + b²

or,

p² = h² -b²

or, b² = h² - b²

in the given attachment, ∆ABC is a right angled triangle.

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Answer 2

Answer:

$(hypotonous)^{2}$, according to Pythagoras theorem

Step-by-step explanation:

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