Question

х
2
BC = x + 2 and AC = x + 3. Find
3. In a right-angled triangle ABC, right angled at B, AB =
value of x.
!
ICI​

Answer 1

Answer:

x^2/4 +(x+2)^2=(x+3)^2

x^2/4+x^2+4x+4=x^2+6x+9

x^2/4+4x+4=6x+9

x^2/4-2x-5=0

x^2-8x-20=0

x^2-10x+2x-20=0

x(x-10)+2(x-10)=9

(x+2)(x-10)=0

x=10