2 blocks of m 10 and 10kg are
connected. A F applied on the
upper string produces an
acceleration of 5m/s2 in the
upward direction. Find T & T'
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Answer:
T = 296 N,
and T' = 148 N
Explanation:
mass 1 = 10 kg
mass2 = 10 kg
acceleration = 5 m/sec
Force = F
Lets assume two blocks like one
so the equation of the motions of combination is = f ( m1 + m2 )g = ( m1 + m2) a
T= ( m1 + m2) ( g + a )
by putting values,
T = ( 10 + 10 ) ( 9.8 + 5 )
= ( 20 ) ( 14.8 )
=296 N
and
T' = m( g + a)
= 10( 9.8 + 5 )
= 10( 14.8 )
= 148 N
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