Question

2 blocks of masses 2 kg and 1 kg are in contact with each other on A frictionless table when a horizontal force of three N is applied to the block of mass 2 kg the value of force of contact between two blocks is?

Answer 1

Answer:

The acceleration of the system is, a = 3/(2 + 1) = (3/3)=1 m/s2

The reaction force experienced by the blocks is equal to the force on 1 kg that makes it move with acceleration ‘a’ which is = 1 × 1 = 1 N

Answer 2

Explanation:

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